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Famous If A=I-2J-3K B=2I J-K And C=I 3J-2K 2023. Given vectors a→, b→,c→are co planers. We need to find value of a+tb⊥c.
Web a = k b + k c (linear dependent) i ^ + 2 j ^ + 3 k ^ = k (2 i ^ + 3 j + k) + k 1 (8 i ^ + 1 3 j ^ + 9 k ^) 2 k + 8 k 1 = 1 3 k + 1 2 k 1 = 2 k 1 = 2 1 , k = 2 − 3 2 a + 3 b − c = 0 C = 3 i ^ + j ^ ∴ a + t b = (2 − t) i ^ + (2 + 2 t) j ^ + (3 + t) k ^.(1) c = 3 i ^ + j ^.(2) since (1) and (2) are perpendicular, their dot product. Web explanation for correct option:
(A) 195 (B) −25I+35J−55K, (B) (A+2B)×(2A−B).
Web given, a = 2i + 2j + 3k, b = −1 + 2j + k and c = 3i + j. ⇒ a⋅c + λb⋅c = 0 We need to find value of a + λb ⊥ c.
Given Vectors A→, B→,C→Are Co Planers.
C = 3 i ^ + j ^ ∴ a + t b = (2 − t) i ^ + (2 + 2 t) j ^ + (3 + t) k ^.(1) c = 3 i ^ + j ^.(2) since (1) and (2) are perpendicular, their dot product. We need to find value of a+tb⊥c. Web explanation for correct option:
Mcq Online Mock Tests 31.
Web a = 2 i ^ + 2 j ^ + 3 k ^; Web find vectors [a b c], when i. Web a = k b + k c (linear dependent) i ^ + 2 j ^ + 3 k ^ = k (2 i ^ + 3 j + k) + k 1 (8 i ^ + 1 3 j ^ + 9 k ^) 2 k + 8 k 1 = 1 3 k + 1 2 k 1 = 2 k 1 = 2 1 , k = 2 − 3 2 a + 3 b − c = 0
Cbse Science (English Medium) Class 12.
⇒ (a + λb)⋅c = 0. Web given, a=2i+2j+3k,b=−1+2j+k and c=3i+j. → a ⋅ → b = abcosθ.
In 3D An Equation In The Form Ax+ By +C Z = D.
Finding the value of λ: If a=3i−j−2k and b=2i+3j+k, find: We're asked to find the angle between two vectors, given their unit vector notations.