Famous B=I-J-K 2023

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Famous B=I-J-K 2023. Cosθ = → a ⋅ → b ab. Θ = arccos⎛⎝→ a ⋅ → b ab ⎞⎠.

If a=(i^+j^ +k^),a⋅b=1 and a×b=j^ −k^, then b is Filo
If a=(i^+j^ +k^),a⋅b=1 and a×b=j^ −k^, then b is Filo from askfilo.com

What is the concept behind it, could you please explain with a diagram? A vector → v in the plane of → a and → b, whose projection on → c is 1 √ 3, is given by Given, a = i + j + k, b = i + j, c = i.

Web Asked Apr 21, 2018 In Mathematics By Nisa (60.2K Points) Closed May 6 By Faiz.


Web to do this, we can use the equation. Now if we compare both. Cosθ = → a ⋅ → b ab.

Web According To The Dot Product Properties.


Angle between two vectors is given as. ( axb) x c = ( a. Where θ is the angle between →a and →b.

Finally, The Cross Product Of Any Vector With Itself Is The Zero Vector ( A × A = 0 ).


Θ = arccos⎛⎝→ a ⋅ → b ab ⎞⎠. A vector → v in the plane of → a and → b, whose projection on → c is 1 √ 3, is given by Given, a = i + j + k, b = i + j, c = i.

You Can Actually Set $A$.


(this is the part from. Given, ( a x b) x c = λ a + μ b. Hence, this is the answer.

Web Cosθ= ∣2I+J−K∣∣I+J+K∣(2I+J−K).(I+J+K) Cosθ= ( 4+1+1)( 1+1+1)(2+1−1) Cosθ= ( 6)( 3)2.


Web by remembering that b × a = − a × b, you can infer that j × i = − k k × j = − i i × k = − j. → a ⋅ → b = abcosθ. Rearranging to solve for angle, θ: